I tried to write output file as a CSV file but getting either an error or not the expected result. I am using Python 3.5.2 and 2.7 also.
Getting error in Python 3.5:
Others have answered that you should open the output file in text mode when using Python 3, i.e.
with open('out.csv', 'w', newline='') as resultFile:
...
But you also need to parse the incoming CSV data. As it is your code reads each line of the input CSV file as a single string. Then, without splitting that line into its constituent fields, it passes the string to the CSV writer. As a result, the csv.writer
will treat the string as a sequence and output each character , including any terminating new line character, as a separate field. For example, if your input CSV file contains:
1,2,3,4
Your output file would be written like this:
1,",",2,",",3,",",4," "
You should change the for
loop to this:
for row in csv.reader(f1):
# process the row
wr.writerow(row)
Now the input CSV file will be parsed into fields and row
will contain a list of strings - one for each field. For the previous example, row
would be:
for row in csv.reader(f1):
print(row)
['1', '2', '3', '4']
And when that list is passed to the csv.writer
the output to the file will be:
1,2,3,4
Putting all of that together you get this code:
import csv
with open('input_1.csv') as f1, open('out.csv', 'w', newline='') as resultFile:
wr = csv.writer(resultFile, dialect='excel')
for row in csv.reader(f1):
wr.writerow(row)