Cos(90) returning a value very close to 0, but I need 0?

Question

The values for temp_x_btm_left = 0 & temp_y_btm_left=1;

angle = 90;

//Moving the bottom left coordinates
_btm_left.real() = (temp_x_btm_left * cos(angle         


        

Answer 1

The "magical epsilon" referred to in previous answers is actually provided by the language via

 #include 
 std::numeric_limits::epsilon();

and

 std::numeric_limits::epsilon();

which is "the difference between 1 and the least value greater than 1 that is representable"