How to print a pointer address without printf

Question

I\'m doing an exercise in which I need to print the memory (address) of a pointer. It would be easy to do it with printf(\"%p\", ..) but I\'m not allowed to use

Answer 1

You could do something like this... You said printf() is off limits, but you said nothing about sprintf.

 print_bytes(char *ptr, int count)
 {
   int i;
   char string[1024];
   string[0] = 0;
   for(i = 0; i < count; i++)
   {
     sprintf(string,"%s %2x", string, *(ptr+i));
   }
   puts(string);
 }

This should loop through count bytes printing out each hexadecimal byte starting from the passed in address in ptr.

Obviously, this makes no attempt to properly size the string array. That should be dynamically sized based on the passed in count.

To substitute write() for puts(), you could use:

 write(1, string, strlen(string)); /* 1 = STDOUT */