How to print a pointer address without printf

Question

I\'m doing an exercise in which I need to print the memory (address) of a pointer. It would be easy to do it with printf(\"%p\", ..) but I\'m not allowed to use

Answer 1

You can try like:

#include 

void print_memory(const void *addr, size_t size)
{
    size_t printed = 0;
    size_t i;
    const unsigned char* pc = addr;
    for (i=0; i> 4) & 0xf;
        g += g >= 10 ? 'a'-10 : '0';
        putchar(g);
        printed++;

        g = *(pc+i) & 0xf;
        g += g >= 10 ? 'a'-10 : '0';
        putchar(g);
        printed++;
        if (printed % 32 == 0) putchar('\n');
        else if (printed % 4 == 0) putchar(' ');
    }
}

int main(void) {
int tab[10] = {0, 23, 150, 255, 12, 16, 21, 42};

print_memory(tab, sizeof(tab)); return (0);

    return 0;
}

Output

0000 0000 1700 0000 9600 0000 ff00 0000 
0c00 0000 1000 0000 1500 0000 2a00 0000 
0000 0000 0000 0000