How to default-initialize local variables of built-in types in C++?

Question

How do I default-initialize a local variable of primitive type in C++? For example if a have a typedef:

typedef unsigned char boolean;//that\'s Microsoft RPC         


        

Answer 1

You could provide a wrapper that behaves as the underlying type through overloaded conversion operators.

#include 

template 
class Type
{
    T t;
public:
    Type(const T& t = T()): t(t) {}
    operator T&() { return t; }
    operator const T&() const { return t; }
};

int main()
{
    Type some_value;
    assert(some_value == '\0');
}

This should be a rather OK usage for conversion operators.