Given a hexadecimal string in Swift, convert to hex value

Question

Suppose I am given a string like this:

D7C17A4F

How do I convert each individual character to a hex value?

So D

Answer 1

Swift 3 version, modified from @Martin R's answer. This variant also accepts incoming string with odd length.

let string = "D7C17A4F"

let chars = Array(string.characters)
let numbers = stride(from: 0, to: chars.count, by: 2).map() {
    strtoul(String(chars[$0 ..< min($0 + 2, chars.count)]), nil, 16)
}