Convert time field H:M into integer field (minutes) in JAVA

后端 未结 5 874
名媛妹妹
名媛妹妹 2021-01-06 14:25

The JTable includes the time field, e.g. \"01:50\". I need to read this value into the integer variable. For this I´d like to convert time into minutes. For instance \"01:50

5条回答
  •  伪装坚强ぢ
    2021-01-06 14:44

    Look the sample below which we are using in our application

    public static int toMinutes( String sDur, boolean bAssumeMinutes ) throws NumberFormatException {
            /* Use of regular expressions might be better */
            int iMin = 0;
            int iHr = 0;
            sDur = sDur.trim();
            //find punctuation
            int i = sDur.indexOf(":");//HH:MM
            if (i < 0) {
                //no punctuation, so assume whole thing is an number
                //double dVal = Double.parseDouble(sDur);
                double dVal = ParseAndBuild.parseDouble(sDur, Double.NaN);
                if (Double.isNaN(dVal)) throw new NumberFormatException(sDur);
                if (!bAssumeMinutes) {
                    //decimal hours so add half a minute then truncate to minutes
                    iMin = (int)((dVal * 60.0) + (dVal < 0 ? -0.5 : 0.5));
                } else {
                    iMin = (int)dVal;
                }
            }
            else {
                StringBuffer sBuf = new StringBuffer(sDur);
                int j = sBuf.indexOf(MINUS_SIGN);
                //check for negative sign
                if (j >= 0) {
                    //sign must be leading/trailing but either allowed regardless of MINUS_SIGN_TRAILS
                    if (j > 0 && j < sBuf.length() -1)
                        throw new NumberFormatException(sDur);                  
                    sBuf.deleteCharAt(j);
                    i = sBuf.indexOf(String.valueOf(":"));
                }
                if (i > 0)
                    iHr = Integer.parseInt(sBuf.substring(0, i)); //no thousands separators allowed
                if (i < sBuf.length() - 1)
                    iMin = Integer.parseInt(sBuf.substring(i+1));
                if (iMin < 0 || (iHr != 0 && iMin >= 60))
                    throw new NumberFormatException(sDur);
                iMin += iHr * 60;
                if (j >= 0) iMin = -iMin;
            }
            return iMin;
        }
    

提交回复
热议问题