Sorting words in order of frequency? (least to greatest)

Question

does any one have any idea how to sort a list of words in the order of their frequency (least to greatest) using the built in collection.sort and a compar

Answer 1

You can compare and extract ideas from the following:

public class FrequencyCount {

    public static void main(String[] args) {

        // read in the words as an array
        String s = StdIn.readAll();
        // s = s.toLowerCase();
        // s = s.replaceAll("[\",!.:;?()']", "");
        String[] words = s.split("\\s+");

        // sort the words
        Merge.sort(words);

        // tabulate frequencies of each word
        Counter[] zipf = new Counter[words.length];
        int M = 0;                                        // number of distinct words
        for (int i = 0; i < words.length; i++) {
            if (i == 0 || !words[i].equals(words[i-1]))   // short-circuiting OR
                zipf[M++] = new Counter(words[i], words.length);
            zipf[M-1].increment();
        }

        // sort by frequency and print
        Merge.sort(zipf, 0, M);                           // sorting a subarray
        for (int j = M-1; j >= 0; j--) {
            StdOut.println(zipf[j]);
        }
    }
}