I\'m creating a small chat application in gRPC right now and I\'ve run into the issue where if a user wants to connect to the gRPC server as a client, I\'d like to broadcast
Another option would be to use a long-polling approach. That is try something like below (code in Python, since that is what I'm most familiar with, but go should be very similar). This was not tested, and is meant to just give you an idea of how to do long-polling in gRPC:
.PROTO defs
-------------------------------------------------
service Updater {
rpc GetUpdates(GetUpdatesRequest) returns (GetUpdatesResponse);
}
message GetUpdatesRequest {
int64 last_received_update = 1;
}
message GetUpdatesResponse {
repeated Update updates = 1;
int64 update_index = 2;
}
message Update {
// your update structure
}
SERVER
-----------------------------------------------------------
class UpdaterServer(UpdaterServicer):
def __init__(self):
self.condition = threading.Condition()
self.updates = []
def post_update(self, update):
"""
Used whenever the clients should be updated about something. It will
trigger their long-poll calls to return
"""
with self.condition:
# TODO: You should probably remove old updates after some time
self.updates.append(updates)
self.condition.notify_all()
def GetUpdates(self, req, context):
with self.condition:
while self.updates[req.last_received_update + 1:] == []:
self.condition.wait()
new_updates = self.updates[req.last_received_update + 1:]
response = GetUpdatesResponse()
for update in new_updates:
response.updates.add().CopyFrom(update)
response.update_index = req.last_received_update + len(new_updates)
return response
SEPARATE THREAD IN THE CLIENT
----------------------------------------------
request = GetUpdatesRequest()
request.last_received_update = -1
while True:
stub = UpdaterStub(channel)
try:
response = stub.GetUpdates(request, timeout=60*10)
handle_updates(response.updates)
request.last_received_update = response.update_index
except grpc.FutureTimeoutError:
pass