Find specific pattern and print complete text block using awk or sed

Question

How can find a specific number in a text block and print the complete text block beginning with the key word \"BEGIN\" and ending with \"

Answer 1

This awk should work:

awk -v s='B: 567' '$0~s' RS= file
BEGIN
A: xyz
B: 56789
C: abc
END
BEGIN
A: ghi
B: 56712
C: pqr
END