How to use execv system call in linux?

Question

I am writing a program using execl to execute my exe file which is testing and it\'s work very well and display the output in the Linux CLI. But I have not idea how to chang

Answer 1

In order to see the difference between execl and execv, here is a line of code executing a

ls -l -R -a

with execl :

execl("/bin/ls", "ls", "-l", "-R", "-a", NULL);

with execv :

char* arr[] = {"ls", "-l", "-R", "-a", NULL};
execv("/bin/ls", arr);

The array of char* sent to execv will be passed to /bin/ls as argv (in int main(int argc, char **argv))

Here is the execl(3) Linux manual page for more detail.