Why are field initializers of a derived class are executed before base classes's initializers

Question

constructors are executed in the order from top to bottom I.E. base\'s first followed by derived one. This arangement is based on an important OOP assurance that an object (

Answer 1

Field initialisers are executed in the constructor, and as the constructor in the base class is called first, all field initialisers are also executed before the derived constructor executes.

Example:

public class Base {

  // field initialiser:
  private string _firstName = "Arthur";

  public string FirstName { get { return _firstName;}}
  public string LastName { get; private set; }

  // initialiser in base constructor:    
  public Base() {
    LastName = "Dent";
  }

}

public class Derived : Base {

  public string FirstNameCopy { get; private set; }
  public string LastNameCopy { get; private set; }

  public Derived() {
    // get values from base class:
    FirstNameCopy = FirstName;
    LastNameCopy = LastName;
  }

}

Test:

Derived x = new Derived();
Console.WriteLine(x.FirstNameCopy);
Console.WriteLine(x.LastNameCopy);

Output:

Arthur
Dent