How do I launch multiple batch files from one batch file with dependency?

Question

I want to run one batch file, that start the other batch files. I looked at a similar question posted here: How to run multiple .BAT files within a .BAT file

I follo

Answer 1

Whenever I have batch files that depend on another I either: 1. nest them; meaning, if batch1 needs to run before batch2, then I add batch2 within batch1. 2. put a 'sleep' call within batch2. This is only possible if you are fairly certain of the startup duration for batch1.

A sample sleep command is:

ping 127.0.0.1 -n 4 > null

This will make the batch file wait for 3 seconds. (Because there are only 3, 1 second sleeps, between each of the 4 echos)

Examples:

start cmd /k CALL D:\jboss-5.1.0.GA-jdk6\jboss-5.1.0.GA\bin\run.bat
ping 127.0.0.1 -n 4 > null
start cmd /k CALL batch1.bat
ping 127.0.0.1 -n 4 > null
start cmd /k CALL batch2.bat
ping 127.0.0.1 -n 4 > null
start cmd /k CALL batch3.bat