function declaration after return statement global variable is not overwritten [duplicate]

Answer 1

This is javascript hoisting behavior. Take a look at this link. In your case, the script is interpreted like this:

var foo = 1;
function bar() {
    function foo() {}
    foo = 10;
    return; 
}

bar();
console.log(foo);

Because:

Function declarations and variable declarations are always moved (“hoisted”) invisibly to the top of their containing scope by the JavaScript interpreter

In your case, when you assign foo = 10;, you're assigning to the local variable. That's why the global variable is still unchanged.