I’ve written a short program in Go to communicate with a sensor through a serial port:
package main
import (
\"fmt\"
\"github.com/tarm/goserial\"
I guess buf gets overwritten after every loop pass. Any suggestions?
Yes, buf
will get overwritten with every call to Read()
.
A timeout on the file handle would be the approach I would take.
s, _ := os.OpenFile("/dev/ttyS0", syscall.O_RDWR|syscall.O_NOCTTY|syscall.O_NONBLOCK, 0666)
t := syscall.Termios{
Iflag: syscall.IGNPAR,
Cflag: syscall.CS8 | syscall.CREAD | syscall.CLOCAL | syscall.B115200,
Cc: [32]uint8{syscall.VMIN: 0, syscall.VTIME: uint8(20)}, //2.0s timeout
Ispeed: syscall.B115200,
Ospeed: syscall.B115200,
}
// syscall
syscall.Syscall6(syscall.SYS_IOCTL, uintptr(s.Fd()),
uintptr(syscall.TCSETS), uintptr(unsafe.Pointer(&t)),
0, 0, 0)
// Send message
n, _ := s.Write([]byte("Test message"))
// Receive reply
for {
buf := make([]byte, 128)
n, err = s.Read(buf)
if err != nil { // err will equal io.EOF
break
}
fmt.Printf("%v\n", string(buf))
}
Also note, if there is no more data read and there is no error, os.File.Read() will return an error of io.EOF
,
as you can see here.