Laravel 5 Pagination with Query Builder

Question

I\'m making a Laravel Pagination based from my query result and be rendered in my view. I\'m following this guide http://laravel.com/docs/5.1/pagination but I get an error:<

Answer 1

this is the way i did, it use query builder and get the same result with pagination

$paginateNumber = 20;

    $key = $this->removeAccents(strip_tags(trim($request->input('search_key', ''))));
    $package_id = (int)$request->input('package_id', 0);
    $movieHasTrailer = MovieTrailer::select('movie_id')->where('status','!=','-1')->distinct('movie_id')->get();

    $movieIds = array();

    foreach ($movieHasTrailer as $index => $value) {
        $movieIds[] = $value->movie_id;
    }


    $keyparams = array();
    $packages = Package::select('package_name','id')->get();

    $whereClause = [
        ['movie.status', '!=', '-1'],
        ['movie_trailers.status', '!=', '-1']
    ];

    if(!empty($key)){
        $whereClause[] = ['movie.title', 'like', '%'.$key.'%'];
        $keyparams['search_key'] = $key;  
    }

    if($package_id !== 0){
        $whereClause[] = ['movie.package_id', '=', $package_id];
        $keyparams['package_id'] = $package_id;  
    }



    $movies = DB::table('movie')
            ->leftJoin('movie_package','movie.package_id','=','movie_package.id')
            ->leftJoin('movie_trailers','movie.id','=','movie_trailers.movie_id')
            ->where($whereClause)
            ->whereIn('movie.id',$movieIds)
            ->select('movie.*','movie_package.package_name','movie_trailers.movie_id as movie_id', 
                DB::raw('count(*) as total_trailers, movie_id')
            )
            ->groupBy('movie.id')
            ->paginate($paginateNumber);