Count the number of max consecutive “a”'s from a string. Python 3

Question

Say that the user inputs:

\"daslakndlaaaaajnjndibniaaafijdnfijdnsijfnsdinifaaaaaaaaaaafnnasm\"

How would you go about finding the highest

Answer 1

Try this:

import collections

def runLenEncode(s):
    start, i = 0, 0;
    answer = []
    while i=thresholds[char]:
            count = repLens[char]
        answer.append(char*count)
    return ''.join(answer)

def maxFilter(encoding, repLens):
    maxCounts = collections.defaultdict(int)
    for char, count in encoding:
        if char in repLens and count > maxCounts[char]:
            maxCounts[char] = count
    maxCounts = dict(maxCounts)
    answer = []
    for char, count in encoding:
        if char in repLens and count==maxCounts[char]:
            count = repLens[char]
        answer.append(char*count)
    return ''.join(answer)

if __name__ == "__main__":
    print('starting')

    s = "daslakndlaaaaajnjndibniaaafijdnfijdnsijfnsdinifaaaaaaaaaaafnnasm"
    encoding = runLenEncode(s)
    print("encoding:", encoding)
    thresholds = {'a':3}
    repLens = {'a':2}
    decoded = runLenFilter(encoding, thresholds, repLens)
    print('lenFilter:', decoded)
    filtered = maxFilter(encoding, repLens)
    print("maxFilter:", filtered)

    print('done')

And the output:

$ python3 myFile.py
starting
encoding: [('d', 1), ('a', 1), ('s', 1), ('l', 1), ('a', 1), ('k', 1), ('n', 1), ('d', 1), ('l', 1), ('a', 5), ('j', 1), ('n', 1), ('j', 1), ('n', 1), ('d', 1), ('i', 1), ('b', 1), ('n', 1), ('i', 1), ('a', 3), ('f', 1), ('i', 1), ('j', 1), ('d', 1), ('n', 1), ('f', 1), ('i', 1), ('j', 1), ('d', 1), ('n', 1), ('s', 1), ('i', 1), ('j', 1), ('f', 1), ('n', 1), ('s', 1), ('d', 1), ('i', 1), ('n', 1), ('i', 1), ('f', 1), ('a', 11), ('f', 1), ('n', 2), ('a', 1), ('s', 1), ('m', 1)]
lenFilter: daslakndlaajnjndibniaafijdnfijdnsijfnsdinifaafnnasm
maxFilter: daslakndlaaaaajnjndibniaaafijdnfijdnsijfnsdinifaafnnasm
done