Please explain what this code is doing (someChar - 48)

Question

I\'m going through some practice problems, and I saw this code:

#include 
#include 

int main(void) {
   char* s = \"357\";
           


        

Answer 1

its adding up 3 + 5 + 7, and then printing

Sum is 15

The -48 part is that it is subtracting the character 0, that is, the ascii value for 0.

So what it does is

'3' - '0' > 51 - 48
'5' - '0' > 53 - 48
'7' - '0' > 55 - 48

As you can see, in C, '0' (character zero) is different from 0 (number 0). They have different values (amongst other things)