Bitwise rotation (Circular shift)

Question

I was trying to make some code in C++ about “bitwise rotation” and I would like to make this by the left shif. I didn’t know how to code this, but I found a little code in “

Answer 1

Following code works great

#include 

std::uint32_t rotl(std::uint32_t v, std::int32_t shift) {
    std::int32_t s =  shift>=0? shift%32 : -((-shift)%32);
    return (v<>(32-s));
}

std::uint32_t rotr(std::uint32_t v, std::int32_t shift) {
    std::int32_t s =  shift>=0? shift%32 : -((-shift)%32);
    return (v>>s) | (v<<(32-s));
}

and of course the test for it.

#include 

int main(){
   using namespace std;
   cout<

maybe I not provided the fastest implementation, but a portable and stable one for sure

Generic version

#include 

template< class T>
inline T rotl( T v, std::int32_t shift){
    std::size_t m = sizeof(v)*std::numeric_limits::digits;
    T s = shift>=0? shift%m: -((-shift)%m)
    return (v<>(m-s));
}

template< class T>
inline T rotr( T v, std::int32_t shift){
    std::size_t m = sizeof(v)*std::numeric_limits::digits;
    T s = shift>=0? shift%m: -((-shift)%m)
    return (v>>s) | (v<<(m-s));
}

Cheers :)