I run the following code from a python interpreter, and expect the insert statement to fail and throw some kind of exception. But it\'s not happening:
Python
Working foreign key support in SQLite is very new -- it was only released in 3.6.19 on October 14th. Are you sure you're using SQLite 3.6.19 or later?
Check the sqlite_version constant in the sqlite3 module. E.g. on a Mac OS X 10.6 system with the default python/sqlite install:
>>> import sqlite3
>>> sqlite3.sqlite_version
'3.6.12'
>>>