C Pointer Arithmetic sizeof(struct)

Question

Here is the code in question

#include 

struct test {
    unsigned char t;
    unsigned short u;
    unsigned char v;
};


int main ()
{
    s         


        

Answer 1

You have a typed pointer.

So when you increment it my 1 (i.e. a + 1) it means a + sizeof(type).

So a + sizeof(type) = a + sizeof(type) * sizeof(type) = a + 6 * 6 (in your case as sizeof(test) = 6)

That's where you are getting 0x24 or 36 from.