floor and ceil with number of decimals

Question

I need to floor a float number with an specific number of decimals.

So:

2.1235 with 2 decimals --> 2.12
2.1276 with 2 decimals --> 2.12  (round         


        

Answer 1

This seems to work (needs no import and works using the // operator which should be faster than numpy, as it simply returns the floor of the division):

a = 2.338888
n_decimals = 2
a = ((a*10**n_decimals)//1)/(10**n_decimals)