Node.js: Capture STDOUT of `child_process.spawn`

Question

I need to capture in a custom stream outputs of a spawned child process.

child_process.spawn(command[, args][, options])

F

Answer 1

You can do it without using a temporary file:

var process = child_process.spawn(command[, args][, options]);
process.stdout.on('data', function (chunk) {
    console.log(chunk);
});