Array of pointers to arrays

Question

I am new to C programming and this is my problem:

I want to store the first value of each array in a new array, then the second value of each array in a new array an

Answer 1

int* (*a[5])[5][5][5] declares an array of 5 pointers to a 3d array of pointers to ints

int* (*(*a[5])[5])[5][5][5] declares an array of 5 pointers to an array of 5 pointers to a 3d array of pointers to ints.

#include 

int main()
{
    int t1[4]={0,1,2,3};
    int t2[4]={4,5,6,7};
    int t3[4]={8,9,10,11};
    int t4[4]={12,13,14,15};
    int (*tab[4])[4]={&t1,&t2,&t3,&t4};
    int i,j,k,l;
    for (i=0; i<4;i++)
    {
        printf("%d\t", (*tab[i])[1]);
    }

    return 0;
}

There's a difference between t2 and &t2. Though they have the same value their types are different. int [4] vs int (*)[4]. The compiler will throw a warning (clang) or error (gcc).

int a[4] is conceptually at compiler level a pointer to an array of 4 as well as being the array itself (&a == a).

int (*a)[4] is conceptually at compiler level a pointer to a pointer to an array of 4 as well as being a pointer to the array itself (a == *a) because it's pointing to an array type where the above is true.