Is multiprocessing.Manager().dict().setdefault() broken?

Question

The its-late-and-im-probably-stupid department presents:

>>> import multiprocessing
>>> mgr = multiprocessing.Manager()
>>> d = mg         


        

Answer 1

items() returns a copy. Appending to a copy does not affect the original. Did you mean this?

>>> d['foo'] =({'bar': 'baz'})
>>> print d.items()
[('foo', {'bar': 'baz'})]