Squaring a number in C++ yields wrong value

Question

If I do

 int n = 100000;
 long long x = n * n;

then x == 1410065408

1410065408 is 2^31, yet I expect x to be 64 bit

Answer 1

Edit - This is another solution to the problem; what this will do is cast the integer values to a long long before the multiplication so you don't get truncation of bits.

Original Posting

int n = 100000;
long long x = static_cast( n ) * static_cast( n );

Edit - The original answer provided by Jossie Calderon was already accepted as a valid answer and this answer adds another valid solution.