variadic function template without formal parameters

Question

This is what I\'m trying to do:

// base case
void f() {}

template 
void f() {
             


        

Answer 1

Since class templates can be partially specialized, another possibility is to use class templates to do the work, and have your function delegate to them:

template
struct caller
{
    static void call() { } // Base case, terminates recursion
};

template
struct caller
{
    static void call()
    {
        // Do something with T
        caller::call();
    }
};

template
void f() {
    caller::call();
}