How can I translate this XPath expression to BeautifulSoup?

Question

In answer to a previous question, several people suggested that I use BeautifulSoup for my project. I\'ve been struggling with their documentation and I just cannot parse it

Answer 1

one option is to use lxml (I'm not familiar with beautifulsoup, so I can't say how to do with it), it defaultly supports XPath

Edit:
try (untested) tested:

soup.findAll('td', 'altRow')[1].findAll('a', href=re.compile(r'/.a\w+'), recursive=False)

I used docs at http://www.crummy.com/software/BeautifulSoup/documentation.html

soup should be a BeautifulSoup object

import BeautifulSoup
soup = BeautifulSoup.BeautifulSoup(html_string)