Please see the code below.
def getSheetName(file_name):
pointSheetObj = []
import xlrd as xl
TeamPointWorkbook = xl.open_workbook(file_name)
I have modified the code I gave as a question and have got what I needed actually,
def getSheetName(file_name):
pointSheetObj = []
import xlrd as xl
TeamPointWorkbook = xl.open_workbook(file_name)
pointSheets = TeamPointWorkbook.sheet_names()
for i in pointSheets:
pointSheetObj.append(tuple((TeamPointWorkbook.sheet_by_name(i),i)))
so if the list (of tuple
) pointSheetObj
is iterated we have name of the sheet at index 1
of the tuple
inside the pointSheetObj
.
By doing this I have got the name and the worksheet object with which I can carry on with other sheet related methods.