How to insert N rows of default values into a table

Question

I have a table containing an identity column as well as a column representing the creation date:

CREATE TABLE dbo.OrderStatus
(
    OrderStatusId int IDENTIT         


        

Answer 1

The Tally Table method can insert large sets of multiple rows, providing the tally table is big enough. This Tally table will handle up to 1000 entries.

WITH Tally (n) AS
(
    -- 1000 rows
    SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
    FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) a(n)
    CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) b(n)
    CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) c(n)
)
--SELECT * FROM Tally;

Create Table #temp (id int, d datetime, GUID uniqueidentifier, str1 nvarchar(1), number int)

insert into #temp
select n, getdate(), newid(), 'a', 101 from tally 
where N<=100 -- THIS IS WHERE YOU INDICATE HOW MANY ROWS

select * from #temp