Typescript: How to call method defined with arrow function in base class using super keyword in child class?

Question

Given

class BaseClass{

  count:number=0;

  public someMethod=():void =>{
      this.count++;
  }
}

class ChildClass extends BaseClass{
  public someMe         


        

Answer 1

Just would like to capture an "answer" to this question from another discussion here: https://typescript.codeplex.com/workitem/2491

Definitely not efficient in terms of memory or processing overhead but it does answer the question.

class Base {
    x = 0;
    constructor() {
        for (var p in this)
            if (!Object.prototype.hasOwnProperty.call(this, p) && typeof this[p] == 'function') {
                var method = this[p];
                this[p] = () => { method.apply(this, arguments); };
                // (make a prototype method bound to the instance)
            }
    }
}

class A extends Base {
    doSomething(value) { alert("A: " + value + " / x == " + this.x); }
}

class B extends A {
    doSomething(value) { alert("B: " + value + " / x == " + this.x ); super.doSomething(value); }
}

var b = new B();
var callback = b.doSomething;
callback("Cool!");