Suppress unused variable warning in C++ => Compiler bug or code bug?

Question

Presently, I am using the following function template to suppress unused variable warnings:

template
void
unused(T const &) {
  /* Do n         


        

Answer 1

The actual way of indicating you don't actually use a parameter is not giving it a name:

int f(int a, float) {
     return a*2;
}

will compile everywhere with all warnings turned on, without warning about the unused float. Even if the argument does have a name in the prototype (e.g. int f(int a, float f);), it still won't complain.