Using purrr::pmap within mutate to create list-column

Question

I understand how to use map to iterate over arguments in a df and create a new list column.

For example,

params <- expand.grid(param_a = c(2, 4,          


        

Answer 1

How about using rowwise and mutate directly without map:

my_fun <- function(param_a, param_b){
  rep(5, param_a) * param_b
}
df.preprocessed <- dplyr::as.tbl(params) %>%
  rowwise() %>% 
  dplyr::mutate(test_var = list(my_fun(param_a, param_b))) %>% 
  tidyr::unnest()