Prepared Statements - Number of Rows

Question

I\'m learning about prepared statements and trying to work with a query that yields multiple rows of results. Right now, I\'m just trying to figure out how to determine the

Answer 1

If you are only interested in the row count instead of the actual rows of data, here is a complete query block with a COUNT(*) call in the SELECT clause.

$conn = new mysqli("host", "user", "pass", "db");
$stmt = $conn->prepare("SELECT COUNT(*) FROM `table` WHERE id= ?");
$stmt->bind_param("s", $id);
$stmt->execute()
$stmt->bind_result($num_rows)
$stmt->fetch()
$num_rows;

Or if you want to know the row count before iterating/processing the rows, one way is to lump the entire resultset (multi-dimensional array) into a variable and call count() before iterating.

$conn = new mysqli("host", "user", "pass", "db");
$sql = "SELECT field1, field2, field3
        FROM table
        WHERE id= ?
        ORDER BY id";
$stmt = $conn->prepare($sql);
$stmt->bind_param("s", $id);
$stmt->execute();
$result = $stmt->get_result();
$resultset = $result->fetch_all(MYSQLI_ASSOC);
echo "
Num: " , count($resultset) , "
";
foreach ($resultset as $row) {
    echo "
Row: {$row['field1']} & {$row['field2']} & {$row['field3']}
";
}

*I have tested both of the above snippets to be successful on my localhost.