How to extract the file name from a file path?

Question

I have the following code:

os.listdir(\"staging\")

# Seperate filename from extension
sep = os.sep

# Change the casing
for n in os.listdir(\"staging\"):
           


        

Answer 1

import os
pathname ='c:\\hello\\dickins\\myfile.py'
head, tail = os.path.split(pathname)
print head
print tail