i need to iterate over a tuple of indices. all indices must be in the range
[0, N)
with the condition i > j
. The toy example I present here deal
You can use product
from itertools
if you don't mind the inefficiency of throwing out most of the generated tuples. (The inefficiency gets worse as the repeat
parameter increases.)
>>> from itertools import product
>>> for p in ((i,j) for (i,j) in product(range(5), repeat=2) if i > j):
... print p
...
(1, 0)
(2, 0)
(2, 1)
(3, 0)
(3, 1)
(3, 2)
(4, 0)
(4, 1)
(4, 2)
(4, 3)
>>> for p in ((i,j,k) for (i,j,k) in product(range(5), repeat=3) if i > j > k):
... print p
...
(2, 1, 0)
(3, 1, 0)
(3, 2, 0)
(3, 2, 1)
(4, 1, 0)
(4, 2, 0)
(4, 2, 1)
(4, 3, 0)
(4, 3, 1)
(4, 3, 2)
Update: Instead of tuple unpacking, using indexing for the filter. This allows the code to be written a little more compactly. Only my_filter
needs to be changed for tuples of varying sizes.
from itertools import product, ifilter
def my_filter(p):
return p[0] > p[1] > p[2]
for p in ifilter(my_filter, product(...)):
print p