Convert rank and partition query to SqlAlchemy

Question

I would like to convert the following query to SqlAlchemy, but the documentation isn\'t very helpful:

select * from (
select *, 
RANK() OVER (PARTITION BY id         


        

Answer 1

use over expression

from sqlalchemy import func

subquery = db.session.query(
    table1,
    func.rank().over(
        order_by=table1.c.date.desc(),
        partition_by=table1.c.id
    ).label('rnk')
).subquery()

query = db.session.query(subquery).filter(
    subquery.c.rnk==1
)