boost-python select between overloaded methods

Question

Assume exist some class Foo with two overloaded methods:

class Foo
{
  ...
   void m1(A& a);
   void m1(B& b);

I need expose one of

Answer 1

Just for completion, it is also possible to have both of them exposed at python side:

void (Foo::*m1_a)(A&) = &Foo::m1;
void (Foo::*m1_b)(B&) = &Foo::m1;

boost::python::class_("Foo")
    .def("m1", m1_a)
    .def("m1", m1_b)