How do I use reflection to get properties explicitly implementing an interface?

Question

More specifically, if I have:

public class TempClass : TempInterface
{

    int TempInterface.TempProperty
    {
        get;
        set;
    }
    int Temp         


        

Answer 1

It's overly complex. You have to reflect over the methods/properties of the Interface type, see if they exist in your class type, and compare them to see if they're the "same" when they do exist.

If something is in the interface but not the type you're testing, it's an explicit implementation. If it's in both, but different between the two, it's an explicit interface.