TypeError: Request path contains unescaped characters, how can I fix this

Question

/*Making http request to the api (Git hub)
create request
parse responce
wrap in a function
*/
var https = require(\"https\");

var username = \'lynndor\';
//CREATIN         


        

Answer 1

Typically, you do not want to use encodeURI() directly. Instead, use fixedEncodeURI(). To quote MDN encodeURI() Documentation...

If one wishes to follow the more recent RFC3986 for URLs, which makes square brackets reserved (for IPv6) and thus not encoded when forming something which could be part of a URL (such as a host), the following code snippet may help:

function fixedEncodeURI(str) { return encodeURI(str).replace(/%5B/g, '[').replace(/%5D/g, ']'); }

There is a similar issue with encodeURIComponent() (source: MDN encodeURIComponent() Documentation), as well as a similar fixedEncodeURIComponent() function. These should be used, rather than the actual encodeURI() or encodeURIComponent() function calls...

To be more stringent in adhering to RFC 3986 (which reserves !, ', (, ), and *), even though these characters have no formalized URI delimiting uses, the following can be safely used:

function fixedEncodeURIComponent(str) { return encodeURIComponent(str).replace(/[!'()*]/g, function(c) { return '%' + c.charCodeAt(0).toString(16); }); }