Initialize integer literal to std::size_t

Question

There are known ways to manipulate the type of an integer literal

0L;  // long
3U;  // unsigned integer
1LL; // long long

What I need is a

Answer 1

There is no dedicated suffix for std::size_t. In C++11, you could create a user-defined literal for it, though:

std::size_t operator "" _sz (unsigned long long int x)
{
  return x;
}

// Usage:

auto s = 1024_sz;

static_assert(std::is_same::value, "He's wrong");

Live example