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Regarding google places API

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南旧
南旧 2021-01-03 15:36

What I want to know is that using Google places API. Basically I want to create a site like www.zomato.com

1) Can I show listing of all restaurants and their individ

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  • 时光说笑
    时光说笑 (楼主)
    2021-01-03 15:44

    If we look at the documentation for the Google Places API, we can see the format of the JSON that a request to the API returns. By using json2csharp, we can then easily generate a C# model for the response to a Google Places query.

    public class Location
{
    public double lat { get; set; }
    public double lng { get; set; }
}

public class Geometry
{
    public Location location { get; set; }
}

public class OpeningHours
{
    public bool open_now { get; set; }
    public List weekday_text { get; set; }
}

public class Photo
{
    public int height { get; set; }
    public List html_attributions { get; set; }
    public string photo_reference { get; set; }
    public int width { get; set; }
}

public class Result
{
    public Geometry geometry { get; set; }
    public string icon { get; set; }
    public string id { get; set; }
    public string name { get; set; }
    public OpeningHours opening_hours { get; set; }
    public List photos { get; set; }
    public string place_id { get; set; }
    public double rating { get; set; }
    public string reference { get; set; }
    public string scope { get; set; }
    public List types { get; set; }
    public string vicinity { get; set; }
}

public class PlacesApiQueryResponse
{
    public List html_attributions { get; set; }
    public List results { get; set; }
    public string status { get; set; }
}



    With a simple HTTP request to the Google Places API, we can then deserialize the query results using Json.NET.
    


    using (var client = new HttpClient())
{
    var response = await client.GetStringAsync(string.Format("https://maps.googleapis.com/maps/api/place/nearbysearch/json?location={0},{1}&radius=500&type=bar&key=YourAPIKey", latitude, longitude));
    var result = JsonConvert.DeserializeObject(response);
}

    
    
    
             
    
                                                        
    
            
            
    
              
                
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