Groovy - File handling from http URL

Question

The files in one of our servers can be accessed via http. So, when we bring up a url similar to the following, we get a list of files/directories in that location:

Answer 1

No, you'll need to do some parsing of the returned HTML.

Given this page as an example: http://central.maven.org/maven2/com/bloidonia/groovy-stream/

We'd need to do something like:

@Grab( 'org.ccil.cowan.tagsoup:tagsoup:1.2.1' )

def url = 'http://central.maven.org/maven2/com/bloidonia/groovy-stream/'.toURL()

new XmlSlurper( new org.ccil.cowan.tagsoup.Parser() ).parseText( url.text )
                                                     .body
                                                     .pre
                                                     .a
                                                     .each { link ->
    if( link.@href.text().endsWith( '/' ) ) {
        println "FOLDER : ${link.text()}"
    }
    else {
        println "FILE   : ${link.text()}"
    }
}

Which prints out:

FOLDER : ../
FOLDER : 0.5.1/
FOLDER : 0.5.2/
FOLDER : 0.5.3/
FOLDER : 0.5.4/
FOLDER : 0.6/
FOLDER : 0.6.1/
FOLDER : 0.6.2/
FILE   : maven-metadata.xml
FILE   : maven-metadata.xml.md5
FILE   : maven-metadata.xml.sha1

Obviously, you'd need to tweak the body.pre.a bit to match the output of your webserver for directory listings