What I need to do is to fill the entire file contents with zeros in the fastest way. I know some linux commands like cp
actually gets what is the best block siz
Fastest and simplest:
int fd = open("file", O_WRONLY);
off_t size = lseek(fd, 0, SEEK_END);
ftruncate(fd, 0);
ftruncate(fd, size);
Obviously it would be nice to add some error checking.
This solution is not what you want for secure obliteration of the file though. It will simply mark the old blocks used by the file as unused and leave a sparse file that doesn't occupy any physical space. If you want to clear the old contents of the file from the physical storage medium, you might try something like:
static const char zeros[4096];
int fd = open("file", O_WRONLY);
off_t size = lseek(fd, 0, SEEK_END);
lseek(fd, 0, SEEK_SET);
while (size>sizeof zeros)
size -= write(fd, zeros, sizeof zeros);
while (size)
size -= write(fd, zeros, size);
You could increase the size of zeros
up to 32768 or so if testing shows that it improves performance, but beyond a certain point it should not help and will just be a waste.