How to send raw SOAP request in Java?

Question

I need to send a raw SOAP request to server. My request looks like

POST http://10.76.243.43:8080/registry/services/xds-iti18 HTTP/1.1
Accept-Encoding: gzip,         


        

Answer 1

Can you try like this: you need to replace the xmldata with yours:

   try {
        String xmldata = " your reuest";
        String hostname = "10.76.243.43";
        int port = 8080;
        InetAddress addr = InetAddress.getByName(hostname);
        Socket sock = new Socket(addr, port);

        //Send header
        String path = "registry/services/xds-iti18";
        BufferedWriter wr = new BufferedWriter(new OutputStreamWriter(sock.getOutputStream(), "UTF-8"));
        wr.write("POST "+path + " HTTP/1.1\r\n");
        wr.write("Host: "+hostname+":"+port+"\r\n");
        wr.write("Content-Length: "+ xmldata.length() + "\r\n");
        wr.write("Content-Type: application/soap+xml; charset=\"utf-8\"\r\n");
        wr.write("\r\n");            //Send data
        wr.write(xmldata);
        wr.flush();

        // Response
        BufferedReader rd = new BufferedReader(new InputStreamReader(sock.getInputStream()));
        String line;
        while ((line = rd.readLine()) != null) {
          System.out.println("Response:"+line);
        }
} catch (Exception e) {
   e.printStackTrace();
}