printing odd and even number printing alternately using threads in C++

Question

Odd even number printing using thread I came across this question and wanted to discuss solution in C++ . What I can think of using 2 binary semaphores odd and even semapho

Answer 1

Solution using condition variable.

#include
#include
#include
using namespace std;
mutex oddevenMu;
condition_variable condVar;
int number = 1;

void printEvenOdd(bool isEven, int maxnubmer)
{
    unique_lock ul(oddevenMu);
    while (number < maxnubmer)
    {
        condVar.wait(ul, [&]() {return number % 2 == isEven;});
        cout << number++ << " ";
        condVar.notify_all();
    }

}

int main(string args[])
{
    thread oddThread(printEvenOdd, false, 100);
    thread evenThread(printEvenOdd, true, 100);
    oddThread.join();
    evenThread.join();
    return 0;
}