Substitution with sed + bash function

Question

my question seems to be general, but i can\'t find any answers.

In sed command, how can you replace the substitution pattern by a value returned by a simple bash fun

Answer 1

Agree with Glenn Jackman. If you want to use bash function in sed, something like this :

sed -rn 's/^([[:digit:].]+)/`date -d @&`/p' file |
while read -r line; do
    eval echo "$line"
done

My file here begins with a unix timestamp (e.g. 1362407133.936).