Why is printf before exevp not running?

Question

I get an output of \"hi!\". Why is this not also printing \"something\"?

#include 
#include 

int main(int argc, char** argv)          


        

Answer 1

The string is in the io buffer - so pull the chain and flush that buffer

i.e. add

fflush(stdout)

after the printf (or add \n to the printf)