Ruby - array intersection (with duplicates)

Question

I have array(1 and 2). How can I get array3 from them?

array1 = [2,2,2,2,3,3,4,5,6,7,8,9]

array2 = [2,2,2,3,4,4,4,4,8,8,0,0,0]

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Answer 1

This is a bit verbose, but assuming you mean where the values are at the same position:

def combine(array1, array2)
    longer_array = array1.length > array2.length ? array1 : array2

    intersection = []
    count = 0
    longer_array.each do |item|
        if array1 == longer_array
            looped_array = array2
        else
            looped_array = array1
        end
        if item == looped_array[count]
            intersection.push(item)
        end
        count +=1
    end
    print intersection
end


array_1 = [2,2,2,2,3,3,4,5,6,7,8,9]
array_2 = [2,2,2,3,4,4,4,4,8,8,0,0,0]


combine(array_1, array_2)

I just wanted to point out that I have no clue how you got to array 3 because index position 3 on all three arrays differ:

array_1[3] = 2

array_2[3] = 3

array_3[3] = 3