How does delete[] know the size of an array?

Question

I am curious how delete[] figures out the size of the allocated memory. When I do something like:

int* table = new int[5];
delete[] table;

Answer 1

in the new[]/delete[] case, what happens memory-wise is same/similar to what happens in new/delete case... the size info is stored inside the (larger) allocated block itself . what is interesting for arrays is that it also uses the size info to know how many objects to call destructors on .